3x^(2/3)-5x^(1/3)-2=0

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Solution for 3x^(2/3)-5x^(1/3)-2=0 equation: 


x in (-oo:+oo)

3*x^(2/3)-(5*x^(1/3))-2 = 0

3*x^(2/3)-5*x^(1/3)-2 = 0

t_1 = x^(1/3)

3*t_1^2-5*t_1^1-2 = 0

3*t_1^2-5*t_1-2 = 0

DELTA = (-5)^2-(-2*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+5)/(2*3) or t_1 = (5-49^(1/2))/(2*3)

t_1 = 2 or t_1 = -1/3

t_1 = -1/3

x^(1/3)+1/3 = 0

1*x^(1/3) = -1/3 // : 1

x^(1/3) = -1/3

( -1/3 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 2

x^(1/3)-2 = 0

1*x^(1/3) = 2 // : 1

x^(1/3) = 2

x^(1/3) = 2 // ^ 3

x = 8

x = 8

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